Java: How to sort string in alphabetical order.

Here compareTo() function is used to sort string in an alphabetical order in java.

According to compareTo() function  a string is less than another if it comes before the other in   dictionary order and a string is greater than another if it comes after the other in dictionary  

order.

If you want to ignore case differences when comparing two strings, use compareToIgnoreCase( ),

 

Code Example:

class StringOrder

{

 static String name[]={“Chittagong”,”Dhaka”,”Rangpur”,”Sonargaon”,”Bangladesh”};

public static void main(String args[])

{

int size= name.length;

String temp=null;

System.out.println(“\n”);

for(int i=0;i<size;i++)

{

for(int j=i+1;j<size;j++)

{

if(name[j].compareTo(name[i])<0)

{

//System.out.println(“name[j]:”+name[j]+”compareTo(name[i]):< 0:”+name[i]);

temp=name[i];

name[i]=name[j];

name[j]=temp;

}}}

for(int i=0;i<size;i++)

{

System.out.println(name[i]);

}}}