Java Basic Problems

Java: How to Know in which line Java Exception Occurred?

There is  a very simple way to know where and which line exception occurs in your java code, and it is  very useful tool for diagnosing an Exception.printStackTrace()  is that simple tool which will help you to diagnose your code in an easy way

It  will tell you what happened  and  where (in which line )  in the code this exception  happened

 printStackTrace()  is  a method of the Throwable class. All Exceptions are a subclass of that class.

It’s a great debugging tool.

Here is the code example with output to show the function of  printStackTrace()

import java.io.*;

class numerator1

{

static String input;

static int intInput;

                        public void myNumerator()

                        {

                                                            try

                                                            {

            BufferedReader br=new BufferedReader(new InputStreamReader(System.in));

            System.out.println(“\n”);

                                                            System.out.println(“Enter the Numeric:”);

                                                            System.out.println(“\n”);

                                                            input=br.readLine();

                                                            intInput=Integer.parseInt(input);

                                                            System.out.println(“\n”);

                                                            System.out.println(“You  have Entered:”+intInput);

                                                            System.out.println(“\n”);

                                                            intInput=intInput/0;

      //It will cause an error as I have divided the input number by zero(0)

      //java.lang.ArithmeticException: / by zero  (Check the Output)        

                                                            System.out.println(“\n”);

                                                            }

                                                            catch(Exception e)

                                                            {

                                                            //System.out.println(“Error:”+e.getMessage());

                                    Exception newEx = new Exception(“Error at:”+new java.util.Date()+””,e);

                                    newEx.printStackTrace();

                                                            }

                        }

public static void main(String args[])

{

numerator1 x=new numerator1();

x.myNumerator();

}

}OUTPUT: